# Find the value of `0.32 bar(58)`

Updated On: 24-7-2021

6.1 k+

300+

Answer

Text Solution

Let

R = 0.32 bar(58) rArr R = 0.32585858

.... ...(i) <br> Here number of figure which are not recurring is 2 and number of figure which are recurring is also 2. <br> then

100 R = 32.585858..

....(ii) <br> and

10000 R = 3258.5858...

....(iii) <br> Substracting (ii) from (iii), we get <br>

9900 R = 3226 rArr R = (1613)/(4950)

<br> Aliter Method :

R = .32 + .0058 + .0058 + .000058 +

..... <br>

= .32 + (58)/(10^(4)) (1 + (1)/(10^(2)) + (1)/(10^(4)) + ....oo)

<br>

= .32 + (58)/(10^(4)) ((1)/(1 - (1)/(100)))

<br>

= (32)/(100) + (58)/(9900) = (3168 + 58)/(9900) = (3226)/(9900) = (1613)/(4950)

Transcript

Time | Transcript |
---|---|

00:00 - 00:59 | Sunil find the value of point 325 1st for we will say let our is equals to point 3258 that means this is this part is repeating fork and that the service point 3258 5858 and Sonal this equation be equal to now just multiplied is with hundreds of this will be hundred and this will be 32 point because if you met 1108 B to B 38.5 8585 name this equation as to multiply this again X hundred that this will be hundred 108 by places so this will be |

01:00 - 01:59 | 35.5 58 and 59 this equation be 3rd now subtract equation from third tract s from third if you subtract Second form third then you will get this will be 9990 and if you subtract is that is 3258 -32 this will be 3226 so from here the value of R will be 3226 / 9990 if I cut it by 2 then this will be 16134 50 value of R is this this is your right |

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